Armstrong number C Program

C Program which tell input number is armstrong or not:

#include <stdio.h>

main()

{

   int n=0,s=0,t=0,r=0;

   printf("Enter an integer: ");

   scanf("%d",&n);

   t=n;

   while( t != 0 )

   {

      r = t%10;

      s = s + r*r*r;

      t = t/10;

   }

   if ( n == s )

      printf("Entered number is an armstrong number.\n");

   else

      printf("Entered number is not an armstrong number.\n");

}

Also by Making Function of it:


#include <stdio.h>
void armstrong(int);
main()
{
    int n=0;

    printf("Enter an integer: ");
    scanf("%d",&n);

    armstrong(n);
}
void armstrong(int n)
{
    int s=0,t=0,r=0;
    
    t=n;

    while( t != 0 )
    {
        r = t%10;
        s = s + r*r*r;
        t = t/10;
    }

    if ( n == s )
        printf("Entered number is an armstrong number.\n");
    else
        printf("Entered number is not an armstrong number.\n");
}

C Program which prints all the armstrong number according to given range:

#include <stdio.h>
void armstrong(int);
main()
{
    int m=0,n=0;

    printf("Enter an integer: ");
    scanf("%d",&m);
    printf("Enter an integer: ");
    scanf("%d",&n);

    printf("All Armstrong number between these range are: \n\n");

    while(m<n)
    {
        armstrong(m);
        m++;
    }
}

void armstrong(int n)
{
    int s=0,t=0,r=0;

    t=n;

    while( t != 0 )
    {
        r = t%10;
        s = s + r*r*r;
        t = t/10;
    }

    if ( n == s )
        printf("%d\n",n);
}

C Programming,

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